(4x)+(x-3)+(x^2+4x+3)=y

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Solution for (4x)+(x-3)+(x^2+4x+3)=y equation: 


Simplifying
(4x) + (x + -3) + (x2 + 4x + 3) = y

Reorder the terms:
(4x) + (-3 + x) + (x2 + 4x + 3) = y

Remove parenthesis around (-3 + x)
(4x) + -3 + x + (x2 + 4x + 3) = y

Reorder the terms:
(4x) + -3 + x + (3 + 4x + x2) = y

Remove parenthesis around (3 + 4x + x2)
(4x) + -3 + x + 3 + 4x + x2 = y

Reorder the terms:
-3 + 3 + (4x) + x + 4x + x2 = y

Combine like terms: -3 + 3 = 0
0 + (4x) + x + 4x + x2 = y
(4x) + x + 4x + x2 = y

Combine like terms: (4x) + x = 5x
5x + 4x + x2 = y

Combine like terms: 5x + 4x = 9x
9x + x2 = y

Solving
9x + x2 = y

Solving for variable 'x'.

Combine like terms: y + -1y = 0
9x + x2 + -1y = 0

The solution to this equation could not be determined.

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